3.1 \(\int x^6 (a+b \text {csch}^{-1}(c x)) \, dx\)

Optimal. Leaf size=110 \[ \frac {1}{7} x^7 \left (a+b \text {csch}^{-1}(c x)\right )+\frac {b x^6 \sqrt {\frac {1}{c^2 x^2}+1}}{42 c}-\frac {5 b \tanh ^{-1}\left (\sqrt {\frac {1}{c^2 x^2}+1}\right )}{112 c^7}+\frac {5 b x^2 \sqrt {\frac {1}{c^2 x^2}+1}}{112 c^5}-\frac {5 b x^4 \sqrt {\frac {1}{c^2 x^2}+1}}{168 c^3} \]

[Out]

1/7*x^7*(a+b*arccsch(c*x))-5/112*b*arctanh((1+1/c^2/x^2)^(1/2))/c^7+5/112*b*x^2*(1+1/c^2/x^2)^(1/2)/c^5-5/168*
b*x^4*(1+1/c^2/x^2)^(1/2)/c^3+1/42*b*x^6*(1+1/c^2/x^2)^(1/2)/c

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Rubi [A]  time = 0.06, antiderivative size = 110, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.417, Rules used = {6284, 266, 51, 63, 208} \[ \frac {1}{7} x^7 \left (a+b \text {csch}^{-1}(c x)\right )+\frac {b x^6 \sqrt {\frac {1}{c^2 x^2}+1}}{42 c}-\frac {5 b x^4 \sqrt {\frac {1}{c^2 x^2}+1}}{168 c^3}+\frac {5 b x^2 \sqrt {\frac {1}{c^2 x^2}+1}}{112 c^5}-\frac {5 b \tanh ^{-1}\left (\sqrt {\frac {1}{c^2 x^2}+1}\right )}{112 c^7} \]

Antiderivative was successfully verified.

[In]

Int[x^6*(a + b*ArcCsch[c*x]),x]

[Out]

(5*b*Sqrt[1 + 1/(c^2*x^2)]*x^2)/(112*c^5) - (5*b*Sqrt[1 + 1/(c^2*x^2)]*x^4)/(168*c^3) + (b*Sqrt[1 + 1/(c^2*x^2
)]*x^6)/(42*c) + (x^7*(a + b*ArcCsch[c*x]))/7 - (5*b*ArcTanh[Sqrt[1 + 1/(c^2*x^2)]])/(112*c^7)

Rule 51

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^(n + 1
))/((b*c - a*d)*(m + 1)), x] - Dist[(d*(m + n + 2))/((b*c - a*d)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^n,
x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && LtQ[m, -1] &&  !(LtQ[n, -1] && (EqQ[a, 0] || (NeQ[
c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 6284

Int[((a_.) + ArcCsch[(c_.)*(x_)]*(b_.))*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[((d*x)^(m + 1)*(a + b*ArcCsch[c*
x]))/(d*(m + 1)), x] + Dist[(b*d)/(c*(m + 1)), Int[(d*x)^(m - 1)/Sqrt[1 + 1/(c^2*x^2)], x], x] /; FreeQ[{a, b,
c, d, m}, x] && NeQ[m, -1]

Rubi steps

\begin {align*} \int x^6 \left (a+b \text {csch}^{-1}(c x)\right ) \, dx &=\frac {1}{7} x^7 \left (a+b \text {csch}^{-1}(c x)\right )+\frac {b \int \frac {x^5}{\sqrt {1+\frac {1}{c^2 x^2}}} \, dx}{7 c}\\ &=\frac {1}{7} x^7 \left (a+b \text {csch}^{-1}(c x)\right )-\frac {b \operatorname {Subst}\left (\int \frac {1}{x^4 \sqrt {1+\frac {x}{c^2}}} \, dx,x,\frac {1}{x^2}\right )}{14 c}\\ &=\frac {b \sqrt {1+\frac {1}{c^2 x^2}} x^6}{42 c}+\frac {1}{7} x^7 \left (a+b \text {csch}^{-1}(c x)\right )+\frac {(5 b) \operatorname {Subst}\left (\int \frac {1}{x^3 \sqrt {1+\frac {x}{c^2}}} \, dx,x,\frac {1}{x^2}\right )}{84 c^3}\\ &=-\frac {5 b \sqrt {1+\frac {1}{c^2 x^2}} x^4}{168 c^3}+\frac {b \sqrt {1+\frac {1}{c^2 x^2}} x^6}{42 c}+\frac {1}{7} x^7 \left (a+b \text {csch}^{-1}(c x)\right )-\frac {(5 b) \operatorname {Subst}\left (\int \frac {1}{x^2 \sqrt {1+\frac {x}{c^2}}} \, dx,x,\frac {1}{x^2}\right )}{112 c^5}\\ &=\frac {5 b \sqrt {1+\frac {1}{c^2 x^2}} x^2}{112 c^5}-\frac {5 b \sqrt {1+\frac {1}{c^2 x^2}} x^4}{168 c^3}+\frac {b \sqrt {1+\frac {1}{c^2 x^2}} x^6}{42 c}+\frac {1}{7} x^7 \left (a+b \text {csch}^{-1}(c x)\right )+\frac {(5 b) \operatorname {Subst}\left (\int \frac {1}{x \sqrt {1+\frac {x}{c^2}}} \, dx,x,\frac {1}{x^2}\right )}{224 c^7}\\ &=\frac {5 b \sqrt {1+\frac {1}{c^2 x^2}} x^2}{112 c^5}-\frac {5 b \sqrt {1+\frac {1}{c^2 x^2}} x^4}{168 c^3}+\frac {b \sqrt {1+\frac {1}{c^2 x^2}} x^6}{42 c}+\frac {1}{7} x^7 \left (a+b \text {csch}^{-1}(c x)\right )+\frac {(5 b) \operatorname {Subst}\left (\int \frac {1}{-c^2+c^2 x^2} \, dx,x,\sqrt {1+\frac {1}{c^2 x^2}}\right )}{112 c^5}\\ &=\frac {5 b \sqrt {1+\frac {1}{c^2 x^2}} x^2}{112 c^5}-\frac {5 b \sqrt {1+\frac {1}{c^2 x^2}} x^4}{168 c^3}+\frac {b \sqrt {1+\frac {1}{c^2 x^2}} x^6}{42 c}+\frac {1}{7} x^7 \left (a+b \text {csch}^{-1}(c x)\right )-\frac {5 b \tanh ^{-1}\left (\sqrt {1+\frac {1}{c^2 x^2}}\right )}{112 c^7}\\ \end {align*}

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Mathematica [A]  time = 0.14, size = 107, normalized size = 0.97 \[ \frac {a x^7}{7}-\frac {5 b \log \left (x \left (\sqrt {\frac {c^2 x^2+1}{c^2 x^2}}+1\right )\right )}{112 c^7}+b \sqrt {\frac {c^2 x^2+1}{c^2 x^2}} \left (\frac {5 x^2}{112 c^5}-\frac {5 x^4}{168 c^3}+\frac {x^6}{42 c}\right )+\frac {1}{7} b x^7 \text {csch}^{-1}(c x) \]

Antiderivative was successfully verified.

[In]

Integrate[x^6*(a + b*ArcCsch[c*x]),x]

[Out]

(a*x^7)/7 + b*Sqrt[(1 + c^2*x^2)/(c^2*x^2)]*((5*x^2)/(112*c^5) - (5*x^4)/(168*c^3) + x^6/(42*c)) + (b*x^7*ArcC
sch[c*x])/7 - (5*b*Log[x*(1 + Sqrt[(1 + c^2*x^2)/(c^2*x^2)])])/(112*c^7)

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fricas [B]  time = 0.80, size = 208, normalized size = 1.89 \[ \frac {48 \, a c^{7} x^{7} + 48 \, b c^{7} \log \left (c x \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}} - c x + 1\right ) - 48 \, b c^{7} \log \left (c x \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}} - c x - 1\right ) + 15 \, b \log \left (c x \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}} - c x\right ) + 48 \, {\left (b c^{7} x^{7} - b c^{7}\right )} \log \left (\frac {c x \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}} + 1}{c x}\right ) + {\left (8 \, b c^{6} x^{6} - 10 \, b c^{4} x^{4} + 15 \, b c^{2} x^{2}\right )} \sqrt {\frac {c^{2} x^{2} + 1}{c^{2} x^{2}}}}{336 \, c^{7}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^6*(a+b*arccsch(c*x)),x, algorithm="fricas")

[Out]

1/336*(48*a*c^7*x^7 + 48*b*c^7*log(c*x*sqrt((c^2*x^2 + 1)/(c^2*x^2)) - c*x + 1) - 48*b*c^7*log(c*x*sqrt((c^2*x
^2 + 1)/(c^2*x^2)) - c*x - 1) + 15*b*log(c*x*sqrt((c^2*x^2 + 1)/(c^2*x^2)) - c*x) + 48*(b*c^7*x^7 - b*c^7)*log
((c*x*sqrt((c^2*x^2 + 1)/(c^2*x^2)) + 1)/(c*x)) + (8*b*c^6*x^6 - 10*b*c^4*x^4 + 15*b*c^2*x^2)*sqrt((c^2*x^2 +
1)/(c^2*x^2)))/c^7

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (b \operatorname {arcsch}\left (c x\right ) + a\right )} x^{6}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^6*(a+b*arccsch(c*x)),x, algorithm="giac")

[Out]

integrate((b*arccsch(c*x) + a)*x^6, x)

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maple [A]  time = 0.08, size = 127, normalized size = 1.15 \[ \frac {\frac {c^{7} x^{7} a}{7}+b \left (\frac {c^{7} x^{7} \mathrm {arccsch}\left (c x \right )}{7}+\frac {\sqrt {c^{2} x^{2}+1}\, \left (8 c^{5} x^{5} \sqrt {c^{2} x^{2}+1}-10 c^{3} x^{3} \sqrt {c^{2} x^{2}+1}+15 c x \sqrt {c^{2} x^{2}+1}-15 \arcsinh \left (c x \right )\right )}{336 \sqrt {\frac {c^{2} x^{2}+1}{c^{2} x^{2}}}\, c x}\right )}{c^{7}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^6*(a+b*arccsch(c*x)),x)

[Out]

1/c^7*(1/7*c^7*x^7*a+b*(1/7*c^7*x^7*arccsch(c*x)+1/336*(c^2*x^2+1)^(1/2)*(8*c^5*x^5*(c^2*x^2+1)^(1/2)-10*c^3*x
^3*(c^2*x^2+1)^(1/2)+15*c*x*(c^2*x^2+1)^(1/2)-15*arcsinh(c*x))/((c^2*x^2+1)/c^2/x^2)^(1/2)/c/x))

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maxima [A]  time = 0.36, size = 158, normalized size = 1.44 \[ \frac {1}{7} \, a x^{7} + \frac {1}{672} \, {\left (96 \, x^{7} \operatorname {arcsch}\left (c x\right ) + \frac {\frac {2 \, {\left (15 \, {\left (\frac {1}{c^{2} x^{2}} + 1\right )}^{\frac {5}{2}} - 40 \, {\left (\frac {1}{c^{2} x^{2}} + 1\right )}^{\frac {3}{2}} + 33 \, \sqrt {\frac {1}{c^{2} x^{2}} + 1}\right )}}{c^{6} {\left (\frac {1}{c^{2} x^{2}} + 1\right )}^{3} - 3 \, c^{6} {\left (\frac {1}{c^{2} x^{2}} + 1\right )}^{2} + 3 \, c^{6} {\left (\frac {1}{c^{2} x^{2}} + 1\right )} - c^{6}} - \frac {15 \, \log \left (\sqrt {\frac {1}{c^{2} x^{2}} + 1} + 1\right )}{c^{6}} + \frac {15 \, \log \left (\sqrt {\frac {1}{c^{2} x^{2}} + 1} - 1\right )}{c^{6}}}{c}\right )} b \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^6*(a+b*arccsch(c*x)),x, algorithm="maxima")

[Out]

1/7*a*x^7 + 1/672*(96*x^7*arccsch(c*x) + (2*(15*(1/(c^2*x^2) + 1)^(5/2) - 40*(1/(c^2*x^2) + 1)^(3/2) + 33*sqrt
(1/(c^2*x^2) + 1))/(c^6*(1/(c^2*x^2) + 1)^3 - 3*c^6*(1/(c^2*x^2) + 1)^2 + 3*c^6*(1/(c^2*x^2) + 1) - c^6) - 15*
log(sqrt(1/(c^2*x^2) + 1) + 1)/c^6 + 15*log(sqrt(1/(c^2*x^2) + 1) - 1)/c^6)/c)*b

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int x^6\,\left (a+b\,\mathrm {asinh}\left (\frac {1}{c\,x}\right )\right ) \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^6*(a + b*asinh(1/(c*x))),x)

[Out]

int(x^6*(a + b*asinh(1/(c*x))), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{6} \left (a + b \operatorname {acsch}{\left (c x \right )}\right )\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**6*(a+b*acsch(c*x)),x)

[Out]

Integral(x**6*(a + b*acsch(c*x)), x)

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